PROGRAM TO FIND WHETHER THE GIVEN NUMBER IS ARMSTRONG OR NOT

PROGRAM TO FIND WHETHER THE GIVEN NUMBER IS ARMSTRONG OR NOT

THOSE NUMBERS WHOSE SUM OF ITS DIGITS TO POWER OF NUMBER OF ITS DIGITS IS EQUAL TO THAT NUMBER ARE KNOWN AS ARMSTRONG NUMBER

FOR EXAMPLE: 153

TOTAL DIGITS IN 153 IS 3 

THEREFORE = 1^3 + 5^3 +3^3

                       =    1   +  125  + 27

                       = 153                    

FOR EXAMPLE: 1634

TOTAL DIGITS IN 1634 IS 4

THEREFORE = 1^4  +  6^4  + 3^4  + 4^4

                       =    1   +  1296   + 81   + 64

                       = 1634                   

// prg to illustrate given number is Armstrong or not

#include<stdio.h>
void main()
{
 printf("enter any number:");

 int n,r,arm=0,temp;

 scanf("%d",&n);

 temp=n;

 while(n != 0)

  {

   r = n % 10;

   n = n / 10;

   arm=arm + (r * r * r);

  }

  if( temp == arm )

   printf("%d  is an armstrong  \n",temp);

  else

   printf("%d  is not a armstrong \n",temp);

}  

OUTPUT: